-6h^2-h+3=0

Solution for -6h^2-h+3=0 equation:

-6h^2-h+3=0

We add all the numbers together, and all the variables

-6h^2-1h+3=0

a = -6; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·(-6)·3
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{73}}{2*-6}=\frac{1-\sqrt{73}}{-12}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{73}}{2*-6}=\frac{1+\sqrt{73}}{-12}
$